There are three ways in which vectors can be multiplied, but none is exactly like the usual algebraic multiplication. As you read this material, keep in mind that a vector-capable calculator will help you multiply vectors only if you understand the basic rules of that multiplication.

**Multiplying a Vector by a Scalar**

If we multiply a vector
$\overrightarrow{a}$
by a scalar *s*, we get a new vector. Its magnitude is
the product of the magnitude of
$\overrightarrow{a}$
and the absolute value of *s*. Its direction is the direction of
$\overrightarrow{a}$
if *s* is positive but the opposite direction if *s* is negative.
To divide
$\overrightarrow{a}$
by *s*, we multiply
$\overrightarrow{a}$
by 1/*s*.

**Multiplying a Vector by a Vector**

There are two ways to multiply a vector by a vector: one way produces a scalar (called the scalar product), and the other produces a new vector (called the vector product). (Students commonly confuse the two ways.)

**The Scalar Product**

The *scalar product* of the vectors and in Fig. 3-18a is written as
$\overrightarrow{a}\cdot \overrightarrow{b}$
and defined to be

$\overrightarrow{a}\cdot \overrightarrow{b}=\mathrm{ab}cos\theta $ (3-20)

where *a* is the magnitude of
$\overrightarrow{a}$, b is the magnitude of
ath>^{o} - θ. Either can be used in
Eq. 3-20, because their cosines are the same.

Note that there are only scalars on the right side of Eq. 3-20 (including the
value of cos θ). Thus
$\overrightarrow{a}$ ⋅
$\overrightarrow{b}$
on the left side represents a *scalar* quantity. Because of the notation,
$\overrightarrow{a}$ ⋅
$\overrightarrow{b}$
is also known as the *dot product* and is spoken as "a dot b."

A dot product can be regarded as the product of two quantities:
(1) the magnitude of one of the vectors and
(2) the scalar component of the second vector along the direction of the first vector.
For example, in Fig. 3-18b,
$\overrightarrow{a}$
has a scalar component a cos θ along the direction of
$\overrightarrow{b}$;
note that a perpendicular dropped from the head of
$\overrightarrow{a}$ onto
$\overrightarrow{b}$
determines that component. Similarly,
math>

If the angle between two vectors is 0^{o}, the component of one vector along
the other is maximum, and so also is the dot product of the vectors. If, instead,
θ is 90°, the component of one vector along the other is zero, and so is the dot product.

Equation 3-20 can be rewritten as follows to emphasize the components:

$\overrightarrow{a}\cdot \overrightarrow{b}=(a\mathrm{cos}\theta )\left(b\right)=\left(a\right)(b\mathrm{cos}\theta )$(3-21)

The commutative law applies to a scalar product, so we can write

$\overrightarrow{a}\cdot \overrightarrow{b}=$ \overrightarrow{b}\cdot \overrightarrow{a}$$

When two vectors are in unit-vector notation, we write their dot product as

$\overrightarrow{a}\cdot \overrightarrow{b}=({a}_{x}\hat{i}+{a}_{y}\hat{j}+{a}_{z}\hat{k})\cdot ({b}_{x}\hat{i}+{b}_{y}\hat{j}+{b}_{z}\hat{k})$(3-22)

which we can expand according to the distributive law: Each vector component
of the first vector is to be dotted with each vector component of the second vector.
By doing so, we can show that

$\overrightarrow{a}\cdot \overrightarrow{b}={a}_{x}{b}_{x}+{a}_{y}{b}_{y}+{a}_{z}{b}_{z}$(3-23)

Figure 3-18 (a) Two vectors
$\overrightarrow{a}$ and
$\overrightarrow{b}$,
with an angle θ between them. (b) Each vector has a
component along the direction of the other vector.

**The Vector Product**

The *vector product* of
$\overrightarrow{a}$ and
$\overrightarrow{b}$, written

$\overrightarrow{a}\times \overrightarrow{b}$,
produces a third vector

C = ab sin θ (3-24)

where θ is the smaller of the two angles between
$\overrightarrow{a}$ and
$\overrightarrow{b}$. (You must use the
smaller of the two angles between the vectors because sin θ and
sin(360^{o} sin - θ) differ in algebraic sign.) Because of the notation,
$\overrightarrow{a}\times \overrightarrow{b}$ is also known as the **cross
product**, and in speech it is "a cross b."

**•** If $\overrightarrow{a}$ and
$\overrightarrow{b}$ are parallel or antiparallel,
$\overrightarrow{a}\times \overrightarrow{b}=0$.
The magnitude of
$\overrightarrow{a}\times \overrightarrow{b}$, which can
be written as
|$\overrightarrow{a}\times \overrightarrow{b}$|, is maximum when
$\overrightarrow{a}$ and
$\overrightarrow{b}$
are perpendicular to each other.

The direction of
$\overrightarrow{c}$
is perpendicular to the plane that contains
$\overrightarrow{a}$ and
$\overrightarrow{b}$.
Figure 3-19a shows how to determine the direction of
$\overrightarrow{c}=\overrightarrow{a}\times \overrightarrow{b}$
with what is known as a *right-hand rule*.
Place the vectors
$\overrightarrow{a}$ and
$\overrightarrow{b}$
tail to tail without altering their orientations, and imagine a line that is
perpendicular to their plane where they meet. Pretend to place your *right*
hand around that line in such a way that your fingers would sweep
$\overrightarrow{a}$ into
$\overrightarrow{b}$
through the smaller angle between them. Your outstretched thumb points in the direction of
$\overrightarrow{c}$.

The order of the vector multiplication is important. In Fig. 3-19b, we are determining the direction of $\overrightarrow{{c}^{\prime}}=$ $\overrightarrow{b}\times \overrightarrow{a}$, so the fingers are placed to sweep $\overrightarrow{b}$ into $\overrightarrow{a}$ through the smaller angle. The thumb ends up in the opposite direction from previously, and so it must be that $\overrightarrow{{c}^{\prime}}=\overrightarrow{\mathrm{-c}}$; that is,

$\overrightarrow{b}\times \overrightarrow{a}=-(\overrightarrow{a}\times \overrightarrow{b})$.(3-25)

In other words, the commutative law does not apply to a vector product. In unit-vector notation, we write

$\overrightarrow{a}\times \overrightarrow{b}=({a}_{x}\hat{i}+{a}_{y}\hat{j}+{a}_{z}\hat{k})\times ({b}_{x}\hat{i}+{b}_{y}\hat{j}+{b}_{z}\hat{k})$,(3-26)

which can be expanded according to the distributive law; that is, each component of the first vector is to be crossed with each component of the second vector. For example, in the expansion of Eq. 3-26, we have

${a}_{x}\hat{i}\times {b}_{y}\hat{j}={a}_{x}{b}_{y}(\hat{i}\times \hat{j})={a}_{x}{b}_{y}\hat{k}$.In the last step we used Eq. 3-24 to evaluate the magnitude of
n the last step we used Eq. 3-24 to evaluate the magnitude of ' as unity.
(These vectors and each have a magnitude of unity, and the angle between
$\hat{i}\times \hat{j}$
as unity. (These vectors
$\hat{i}$ and
$\hat{j}$
each have a magnitude of unity, and the angle between them is 90^{o.)
Also, we used the right-hand rule to get the direction of
$\hat{i}\times \hat{j}$
as being in the positive direction of the z axis (thus in the direction of
$\hat{k}$).}

Continuing to expand Eq. 3-26, you can show that

$\overrightarrow{a}\times \overrightarrow{b}=({a}_{y}{b}_{z}-{b}_{y}{a}_{z})\hat{i}+({a}_{z}{b}_{x}-{b}_{z}{a}_{x})\hat{j}+({a}_{x}{b}_{y}-{b}_{x}{a}_{y})\hat{k}$ (3-27)A determinant or a vector-capable calculator can also be used. To check whether any xyz coordinate system is a right-handed coordinate system, use the right-hand rule for the cross product $\hat{i}\times \hat{j}=\hat{k}$ with that system. If your fingers sweep $\hat{i}$ (positive direction of x) into $\hat{j}$ (positive direction of y) with the outstretched thumb pointing in the positive direction of z (not the negative direction), then the system is right-handed.

Figure 3-19 Illustration of the right-hand rule for vector products. (a) Sweep vector
$\overrightarrow{a}$
into vector
$\overrightarrow{b}$
with the fingers of your right hand.
Your outstretched thumb shows the direction of vector
$\overrightarrow{c}=\overrightarrow{a}\times \overrightarrow{b}$. (b) Showing that
$\overrightarrow{a}\times \overrightarrow{b}$
is the reverse of
$\overrightarrow{b}\times \overrightarrow{a}$.

**About the Authors**

David Halliday was an American physicist known for his physics textbooks, *Physics and
Fundamentals of Physics*, which he wrote with Robert Resnick. Both textbooks have
been in continuous use since 1960 and are available in more than 47 languages.

Robert Resnick was a physics educator and author of physics textbooks. He was born in Baltimore, Maryland on January 11, 1923 and graduated from the Baltimore City College high school in 1939. He received his B.A. in 1943 and his Ph.D. in 1949, both in physics from Johns Hopkins University.

The 10th edition of Halliday's Fundamentals of Physics, Extended building upon previous issues by offering several new features and additions. The new edition offers most accurate, extensive and varied set of assessment questions of any course management program in addition to all questions including some form of question assistance including answer specific feedback to facilitate success. The text also offers multimedia presentations (videos and animations) of much of the material that provide an alternative pathway through the material for those who struggle with reading scientific exposition.

Furthermore, the book includes math review content in both a self-study module for more in-depth review and also in just-in-time math videos for a quick refresher on a specific topic. The Halliday content is widely accepted as clear, correct, and complete. The end-of-chapters problems are without peer. The new design, which was introduced in 9e continues with 10e, making this new edition of Halliday the most accessible and reader-friendly book on the market.

A Reader says,"As many reviewers have noted, this is a great physics book used widely in university technical programs as a first course in technical physics, with calculus. I find it is the one book I start with when trying to understand physical concepts at a useful but basic level. It has broad coverage and is well written . To go beyond this book requires specialized books on each topic of interest (electromagnetics, quantum mechanics, thermodynamics, etc.)."

Reader Frank says, "The treatment is sound, thorough, and clear. I've owned the early editions of Halliday and Resnick for years. I'm very happy that I updated my library with this 10th edition. The topics are covered in a very logical order. The study features and worked examples are outstanding. Don't hesitate to buy this book! Reading it is awesome on the Kindle app on the iPad."

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